Barcode gen online5/2/2024 If we have some lowercase, let's choose B. For example if we have only digits, the C would be good one. According to the signs in our code we shoud choose dictionary. There are three dictionaries: A, B and C (in the table below). This is a bit simplified descpription, but usable in most cases. įinaly we add 101 to the code and that's it. In this place we are in the middle of the code and we have to paste: 01010.įor the rest of the digits whe use R dictionary. As our first digit is one, we use L for the fifth and G for sixth and seventh: 0110001, 0000101, 0010001. We use L:įor the fifth digit is the first is in (0, 1, 4, 5, 9)įor the sixth digit is the first is in (0, 2, 5, 6, 7)įor the seventh digit is the first is in (0, 3, 6, 8, 9) Here we have to use G because 1 is none of (0, 4, 7, 8) and for four we use 0011101. We use L for the fourth digit if first one is one of (0, 4, 7, 8), else we use G. The fourth digits dictionary also depends on the first one. So here we have on the first digit 1, so let's use L and for three and it would be 0111101. If it is smaller than four, we use L dictionary. Then we use L dictionary to represent the second digit of the code (the second, not the first). L contains - first is for 0, next for 1 then for 2 and so on. Next step is to convert those digits into string of one and zero. Every time you use Let's barcode to generate EAN13 code, if thirteen digit is different than control number, it is replaced by it. 162%10 = 2 and 10 - 2 = 8 (when rest of division is 0 we use 0), so eight is a control digit and a whole code is 1234567890128. (digit + 3 * digit + digit + 3 * digit + digit + 3 * digit + digit + 3 * digit + digit + 3 * digit + digit + 3 * digit) by 10. Last one is a control number calculated as ten minus the rest of division:
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